2x^2+80x=26x

Solution for 2x^2+80x=26x equation:

2x^2+80x=26x

We move all terms to the left:

2x^2+80x-(26x)=0

We add all the numbers together, and all the variables

2x^2+54x=0

a = 2; b = 54; c = 0;
Δ = b2-4ac
Δ = 542-4·2·0
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-54}{2*2}=\frac{-108}{4}
=-27
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+54}{2*2}=\frac{0}{4}
=0
$